Theoretical Aspects of Lexical Analysis/Exercise 3: Difference between revisions

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New page: Use Thompson's algorithm to build the NFA for the following regular expression. Build the corresponding DFA and minimize it. * <nowiki>((ε|a)b)*</nowiki>
 
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__NOTOC__
<div class="section-container auto" data-section>
  <div class="section">
    <p class="title" data-section-title>Problem</p>
    <div class="content" data-section-content>
<!-- ====================== START OF PROBLEM ====================== -->
Use Thompson's algorithm to build the NFA for the following regular expression. Build the corresponding DFA and minimize it.
Use Thompson's algorithm to build the NFA for the following regular expression. Build the corresponding DFA and minimize it.


* <nowiki>((ε|a)b)*</nowiki>
* '''<nowiki>((ε|a)b)*</nowiki>'''
<!-- ====================== END OF PROBLEM ====================== -->
    </div>
  </div>
  <div class="section">
    <p class="title" data-section-title>Solution</p>
    <div class="content" data-section-content>
<!-- ====================== START OF SOLUTION ====================== -->
The non-deterministic finite automaton (NFA), built by applying Thompson's algorithm to the regular expression '''<nowiki>((ε|a)b)*</nowiki>''' is the following:
<kroki lang="graphviz">
digraph nfa {
    { node [shape=circle style=invis] start }
  rankdir=LR; ratio=0.5
  node [shape=doublecircle,fixedsize=true,width=0.2,fontsize=10]; 8
  node [shape=circle,fixedsize=true,width=0.2,fontsize=10];
  start -> 0
  0 -> 1; 0 -> 8
  1 -> 2; 1 -> 4
  2 -> 3;
  3 -> 6
  4 -> 5 [label="a",fontsize=10]
  5 -> 6
  6 -> 7 [label="b",fontsize=10]
  7 -> 1; 7 -> 8
  fontsize=10
}
</kroki>
 
Applying the determination algorithm to the above NFA, the following determination table is obtained:
{| cellspacing="2"
! style="padding-left: 20px; padding-right: 20px; background: wheat;" | I<sub>n</sub>
! style="padding-left: 20px; padding-right: 20px; background: wheat;" | α∈Σ
! style="padding-left: 20px; padding-right: 20px; background: wheat;" | move(I<sub>n</sub>, α)
! style="padding-left: 20px; padding-right: 20px; background: wheat;" | ε-closure(move(I<sub>n</sub>, α))
! style="padding-left: 20px; padding-right: 20px; background: wheat;" | I<sub>n+1</sub> = ε-closure(move(I<sub>n</sub>, α))
|-
! style="font-weight: normal; align: center; background: #ffffcc;" | -
! style="font-weight: normal; align: center; background: #ffffcc;" | -
! style="font-weight: normal; align: center; background: #ffffcc;" | 0
! style="font-weight: normal; align: left;  background: #ffffcc;" | 0, 1, 2, 3, 4, 6, '''8'''
! style="font-weight: normal; align: center; background: #ffffcc;" | '''0'''
|-
! style="font-weight: normal; align: center; background: #e6e6e6;" | 0
! style="font-weight: normal; align: center; background: #e6e6e6;" | a
! style="font-weight: normal; align: center; background: #e6e6e6;" | 5
! style="font-weight: normal; align: left;  background: #e6e6e6;" | 5, 6
! style="font-weight: normal; align: center; background: #e6e6e6;" | 1
|-
! style="font-weight: normal; align: center; background: #e6e6e6;" | 0
! style="font-weight: normal; align: center; background: #e6e6e6;" | b
! style="font-weight: normal; align: center; background: #e6e6e6;" | 7
! style="font-weight: normal; align: left;  background: #e6e6e6;" | 1, 2, 3, 4, 6, 7, '''8'''
! style="font-weight: normal; align: center; background: #e6e6e6;" | '''2'''
|-
! style="font-weight: normal; align: center; background: #ffffcc;" | 1
! style="font-weight: normal; align: center; background: #ffffcc;" | a
! style="font-weight: normal; align: center; background: #ffffcc;" | -
! style="font-weight: normal; align: left;  background: #ffffcc;" | -
! style="font-weight: normal; align: center; background: #ffffcc;" | -
|-
! style="font-weight: normal; align: center; background: #ffffcc;" | 1
! style="font-weight: normal; align: center; background: #ffffcc;" | b
! style="font-weight: normal; align: center; background: #ffffcc;" | 7
! style="font-weight: normal; align: left;  background: #ffffcc;" | 1, 2, 3, 4, 6, 7, '''8'''
! style="font-weight: normal; align: center; background: #ffffcc;" | '''2'''
|-
! style="font-weight: normal; align: center; background: #e6e6e6;" | 2
! style="font-weight: normal; align: center; background: #e6e6e6;" | a
! style="font-weight: normal; align: center; background: #e6e6e6;" | 5
! style="font-weight: normal; align: left;  background: #e6e6e6;" | 5, 6
! style="font-weight: normal; align: center; background: #e6e6e6;" | 1
|-
! style="font-weight: normal; align: center; background: #e6e6e6;" | 2
! style="font-weight: normal; align: center; background: #e6e6e6;" | b
! style="font-weight: normal; align: center; background: #e6e6e6;" | 7
! style="font-weight: normal; align: left;  background: #e6e6e6;" | 1, 2, 3, 4, 6, 7, '''8'''
! style="font-weight: normal; align: center; background: #e6e6e6;" | '''2'''
|}
 
{| width="100%"
! style="text-align: left; font-weight:normal; vertical-align: top; width: 50%;" |Graphically, the DFA is represented as follows:
 
<kroki lang="graphviz">
digraph dfa {
    { node [shape=circle style=invis] start }
  rankdir=LR; ratio=0.5
  node [shape=doublecircle,fixedsize=true,width=0.2,fontsize=10]; 0 2
  node [shape=circle,fixedsize=true,width=0.2,fontsize=10];
  start -> 0
  0 -> 1 [label="a"]
  0 -> 2 [label="b"]
  1 -> 2  [label="b"]
  2 -> 1 [label="a"]
  2 -> 2 [label="b"]
  fontsize=10
}
</kroki>
 
Given the minimization tree to the right, the final minimal DFA is:
<kroki lang="graphviz">
digraph dfamin {
    { node [shape=circle style=invis] start }
  rankdir=LR; ratio=0.5
  node [shape=doublecircle,fixedsize=true,width=0.3,fontsize=10]; 02
  node [shape=circle,fixedsize=true,width=0.2,fontsize=10]; 1
  start -> 02
  02 -> 1 [label="a"]
  02 -> 02 [label="b"]
  1 -> 02 [label="b"]
  fontsize=10
}
</kroki>
 
! style="text-align: left; font-weight:normal; vertical-align: top; width: 50%;" | The minimization tree is as follows.
 
<kroki lang="graphviz">
digraph mintree {
  node [shape=none,fixedsize=true,width=0.2,fontsize=10]
  "{0, 1, 2}" -> "{1}" [label="NF",fontsize=10]
  "{0, 1, 2}" -> "{0, 2}" [label="  F",fontsize=10]
  "{0, 2}" -> "{0,2} " [label="  a,b",fontsize=10]
  fontsize=10
}
</kroki>
|}
<!-- ====================== END OF SOLUTION ====================== -->
    </div>
  </div>
</div>
 
[[category:Compiladores]]
[[category:Ensino]]
 
[[en:Theoretical Aspects of Lexical Analysis]]

Latest revision as of 18:24, 26 April 2026

Problem

Use Thompson's algorithm to build the NFA for the following regular expression. Build the corresponding DFA and minimize it.

  • ((ε|a)b)*

Solution

The non-deterministic finite automaton (NFA), built by applying Thompson's algorithm to the regular expression ((ε|a)b)* is the following:

Applying the determination algorithm to the above NFA, the following determination table is obtained:

In α∈Σ move(In, α) ε-closure(move(In, α)) In+1 = ε-closure(move(In, α))
- - 0 0, 1, 2, 3, 4, 6, 8 0
0 a 5 5, 6 1
0 b 7 1, 2, 3, 4, 6, 7, 8 2
1 a - - -
1 b 7 1, 2, 3, 4, 6, 7, 8 2
2 a 5 5, 6 1
2 b 7 1, 2, 3, 4, 6, 7, 8 2
Graphically, the DFA is represented as follows:

Given the minimization tree to the right, the final minimal DFA is:

The minimization tree is as follows.
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